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Simplify co(): remove variables that are only used once

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Originally committed as revision 14301 to svn://svn.ffmpeg.org/ffmpeg/trunk
This commit is contained in:
Vitor Sessak 2008-07-19 15:32:29 +00:00
parent 28bb9eb24b
commit 6bc5714be6
1 changed files with 3 additions and 5 deletions
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8
libavcodec/ra288.c
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@ -140,7 +140,6 @@ static void prodsum(float *tgt, const float *src, int len, int n)
static void co(int n, int i, int j, const float *in, float *out, float *st1, static void co(int n, int i, int j, const float *in, float *out, float *st1,
float *st2, const float *table) float *st2, const float *table)
{ {
int a, b, c;
unsigned int x; unsigned int x;
const float *fp; const float *fp;
float buffer1[37]; float buffer1[37];
@ -148,16 +147,15 @@ static void co(int n, int i, int j, const float *in, float *out, float *st1,
float work[111]; float work[111];
/* rotate and multiply */ /* rotate and multiply */
c = (b = (a = n + i) + j) - i;
fp = st1 + i; fp = st1 + i;
for (x=0; x < b; x++) { for (x=0; x < n + i + j; x++) {
if (x == c) if (x == n + j)
fp=in; fp=in;
work[x] = *(table++) * (*(st1++) = *(fp++)); work[x] = *(table++) * (*(st1++) = *(fp++));
} }
prodsum(buffer1, work + n, i, n); prodsum(buffer1, work + n, i, n);
prodsum(buffer2, work + a, j, n); prodsum(buffer2, work + n + i, j, n);
for (x=0;x<=n;x++) { for (x=0;x<=n;x++) {
*st2 = *st2 * (0.5625) + buffer1[x]; *st2 = *st2 * (0.5625) + buffer1[x];